حساب دیفرانسیل و انتگرال چندمتغیره
Multivariable Calculus
مباحث حساب دیفرانسیل و انتگرال توابع چندمتغیره.
ریاضی عمومی کنکور ارشد علوم کامپیوتر
کارتها · 17
Convert a radially symmetric integral over the whole plane to polar form, reducing it to a single improper p-integral in r.
Compute an iterated double integral from the inside out, treating the outer variable as a constant during the inner integration.
Minimize the plane-distance formula over the surface, often collapsing to an algebraic inequality.
For a plane curve r(t)=(x(t),y(t)) , the radius of curvature is R=1/κ with κ= x'y''-y'x'' /((x')^2+(y')^2)^(3/2) .
Convert a hard closed line integral into a curl flux through any bounding surface.
The arc length of y=f(x) is ∫√(1+(y')^2) dx ; for the catenary y=acosh(x/a) the identity 1+sinh^2=cosh^2 erases the square root, giving length asinh(x_1/a) .
A line plus a point not on it fixes a plane: build two in-plane directions, cross them for the normal, and write the point-normal equation.
Slice a solid perpendicular to one axis, integrate the cross-sectional area A(y); for a sphere drilled through its center, the leftover ring's volume depends only on the ring's height, not the sphere's radius.
The outward flux of a vector field through a closed surface equals the triple integral of its divergence over the enclosed solid.
At every point the gradient points toward the fastest increase, and its magnitude is exactly that maximum rate of change.
When a system implicitly defines several variables in terms of others, differentiate the equations in place and solve a small linear system (Jacobian) for the partials — no explicit formulas needed.
How to transform a second-order PDE under a linear change of variables: build the first-order operators from the chain rule, apply them twice to get the second derivatives, and substitute to simplify (e.g. the wave equation into canonical form).
For a solid with rotational symmetry, switch to cylindrical coordinates ( dV=r dz dr dθ ) and integrate ρ r^2 to get the moment of inertia I_z about the axis.
Revolving a curve sweeps a surface whose area is ∫ 2π(radius) ds , where ds is arc length — pick the variable so the radius is the distance to the axis.
The mass of a solid is M=iiint_V ρ dV — integrate the (possibly variable) density over the region; when ρ is constant this collapses to ρcdotvolume .
A limit of f(x,y) as (x,y)→(a,b) exists only if it equals the same value along every path to (a,b) . Finding two paths that give different values proves the limit does not exist.
The area of the piece of a surface z=f(x,y) lying above a region R in the xy-plane is the double integral over R of √(1+f_x²+f_y²) — the local stretch factor between the surface and its shadow.